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with degree of 4, that has zeros -2, 2, 3i

2007-05-05 12:43:24 · 2 answers · asked by erik m 1 in Science & Mathematics Mathematics

2 answers

If 3i is a root, then - 3i must be also.

y = (x+2)(x-2)(x-3i)(x+3i)

Mult together is you need to.

y = (x^2 - 4)(x^2 + 9)

y = x^4 + 5x^2 - 36

2007-05-05 13:06:22 · answer #1 · answered by richardwptljc 6 · 0 0

Let's assume your polynomial has real coefficients.
Then -3i is its 4th root, because if a+bi is a root,
so is a-bi.
So the answer is
P(x) = (x+2)(x-2)(x+3i)(x-3i) = (x²-4)(x²+9) = x^4 + 5x² - 36.

2007-05-05 21:13:57 · answer #2 · answered by steiner1745 7 · 0 0

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