how do i solve a quadratic formula problem?

Answer 1

You are not solving the formula, you are solving a quadratic equation of the form a x^2 + b x + c =0

find the coefficients a, b, and c
Then plug into formula x =

-b +/- sqrt (b^2 - 4ac)
----------------------------
............2a....................

Answer 2

I've tried to do the whole thing in my head since 9th grade, but taking it in a couple of steps is easier:

3x² - 4x + 2 = 0

the formula goes together in about 4 pieces:

2a is 2(3) = 6, -b is 4, b² is (-4)² = 16, -4ac is -4(3)(2) = -24, so

x = 4/6 ± √( 16 - 24) / 6
x = 2/3 ± √-8 / 6
x = 2/3 ± 2i√2 / 6
x = 2/3 ± i√2 / 3

It's when you run into several steps simplifying the radical that things get long.

Answer 3

-b +or - the square root of b squared - 4 ac divided by 2a

i know that sound complicated but it really isn't too bad. i do one for you, but i just made this up and it won't let me use superscript so i don't really know how much help this will be.

6xsquared + 3x - 8

-3 +or- square root of[(3 X 3) - (4 X 6 X 8)] divided by (2 X 6)
-3 + or - the square root of (9 - 192) divided by 12
-3 + or - the square root of (-183) divided by 12

that's the answer i don't if that helped if i had the actual problem i could have done better, b/c the answer would have made more sense.

Answer 4

Please don't listen to Jay Girl. Listen to qualiashe instead.

A is the coefficient of the squared variable (like x^2), B is the coefficient of the variable to the first power (x) and C is the constant in your equation.

Answer 5

as far as i can tell by your question you would take your inputs put them into the formula usually in a calculator and it should give you your answer

Answer 6

its easy you take the first or the number with the largest variable as A. followed by the next as B and the next as C then you substitute it into the formular