chem help pleaseee!!!??

Question

6CO2 (g) + 6H2O (l) ---> C6H12O6 (s) + 6O2 (g)

∆H = 2820 kJ

For the above reaction tell how the amount of C6H12O6 (s) present at equilibrium would be affected by each of the following:

a) some CO2 (g) is added
b) the temperature is raised
c) the volume is decreased
d) some O2 (g) is removed
e) some of the C6H12O6 (s) is removed
f) a catalyst is added
g) some H2O is removed

The answers are supposed to be in the form of : shift left/right

I know the first answer is shift right

10 points to anyone who can answer these!!!!

Answer 1

1 right
2 right
3 left
4 left
5 right
6 left

Answer 2

you need to use Le Chatelier's principle and actually learn how to do it yourself, b/c it will be on your test and people just giving you the answers won't help.

if you add reactant it will shirt to the left
if you add product it will shift to the right
if you remove reactant it will shift to the right
if you remove product it will shift to the left
if you increase the pressure it will shift to the side with fewer moles of gas
increase temp it will shift to make the rxn endothermic
decrease temp it will shift to make the rxn exothermic
catalyst have no effect on equilibrium it just speeds up the process

Answer 3

Well, I am a chemist. Here are your answeres that you want.

a) more products
b) faster reaction
c) more products
d) more products
e) less products
f) faster reaction
g) less products

Answer 4

a) more products
b) faster reaction
c) more products
d) more products
e) less products
f) faster reaction
g) less products