3x(x-5)+16= - x
I got x= -12 and x = -16
2007-05-05 06:37:51 · 5 answers · asked by confused 1 in Science & Mathematics ➔ Mathematics
No,
3x(x-5)+16= - x
<=> 3x^2-15x +16 =-x
<=> 3x^2-14x +16 = 0
<=>x^2-14/3 +16/3 =0
Formula:
x = 7/3 + sqrt(49/9-16/3) = 8/3 v x= 7
/3 -1/3 = 2
Testing it:
3*2(2-5)+16 = -2 = -2
3*8/3(8/3-5) +16 = -8/3 = -8/3
Edit: OK.
2007-05-05 06:47:15 · answer #1 · answered by Anonymous · 0⤊ 1⤋
3x² - 15x + 16 = - x
3x² - 14 x + 16 = 0
(3x - 8).(x - 2) = 0
x = 8 / 3, x = 2
2007-05-05 07:39:05 · answer #2 · answered by Como 7 · 0⤊ 0⤋
Distribute the 3x to the terms inside the parentheses:
3x^2-15x+16=-x
Put everything on one side of the equation:
3x^2-14x+16=0
Factor:
(3x-8)(x-2)=0
Set each factor equal to zero and solve:
3x-8=0 x-2=0
x=2, x=8/3
Whatever.
2007-05-05 06:43:13 · answer #3 · answered by victoria 5 · 1⤊ 1⤋
3x(x-5)+16= - x
3x^2-15x+16= -x
3x^2-14x+16=0
x= 8/3 or x = 2
como how did you write the power like that?
2007-05-05 07:26:06 · answer #4 · answered by Anonymous · 0⤊ 0⤋
3x(x-5)+16= - x
3x^2 + 15x +16 = -x
3x^2 + 16x +16 = 0
(3x + 4 )(x + 4 ) = 0
x = -4/3, -4
2007-05-05 06:45:04 · answer #5 · answered by John S 6 · 0⤊ 2⤋
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2015-01-24 08:12:36 · answer #6 · answered by Anonymous · 0⤊ 0⤋