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How would I solve 4 + 5 / x^2 = 2/x ????

2007-05-05 06:35:43 · 2 answers · asked by confused 1 in Science & Mathematics Mathematics

2 answers

First multiply by x^2 to move all the x's out of the denominators...

4 + 5/x^2 = 2/x
4x^2 + 5 = 2x
4x^2 - 2x + 5 = 0

x = ( -(-2) +/- sqrt(2^2 - 4*4*2 ))/ (2*4)
x = (2 +/- sqrt(-28))/8
x = (1 +/- sqrt(7)i)/4

The discriminant (b^2 - 4ac = -28) is negative so there are no solutions except in imaginary numbers.

2007-05-05 06:44:59 · answer #1 · answered by McFate 7 · 0 0

Multiply all terms by x² to get:

4x² + 5 = 2x

4x² - 2x + 5 = 0 it does not have real solutions though.

Check the equation was copied correctly.

2007-05-05 13:48:48 · answer #2 · answered by sumzrfun 3 · 0 0

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