Heat Capacity Lab?

Question

mass of slug: 17.90 grams

intial temperature of SBC (simple bomb calorimeter): 21.91 degrees Celcius

Max. temp: 25 degrees celcius

slug: length x width= 5cm x 1cm

radius: 0.6 cm

Questions:

Find Q for Water

Specific heat capacity the slug.

Density of Metal


(density of water is 1g/ml)

Answer 1

First we need to deal with the heat gained by the water

q = m Cp delta T

q = heat gained
m = mass. Calculate the volume fo your calorimeter in cm3. This is apossible problem here because it is not really clear how much water you have. The information is about the volume of the slug. You need the volume of the calorimeter, or better, the volume of the water. Then you can use the density of the water to get the mass.
Cp = specific heat for water is 1 cal /g oC

The density of the metal is straightforward.

D = M/V

You are given the mass and you can calulate the volume of the slug and then divide. But I am confused here as well. The slug dimensions gives as length and with makes it seem rectangualr in shape. But then you suddenly give a radius, which presumes a cylindrical shape.

I think you should clarify your data in order to really proceed.

Answer 2

Jack i am going to about common your information above. Mass of metallic l3.5 grams Temp of seventy 5 ml water or similar as seventy 5 grams of water = 20.5 ranges C Temp boiling water containing the heated metallic= l00 ranges C Temp of cool water after warm metallic is positioned in it and it has absorbed the warmth ability from the metallic 24 ranges C warmth received with the help of the cool water = warmth lost with the help of the warm metallic. warmth received with the help of cool water = seventy 5 gms water circumstances ( a million calorie/gm/degree C)( 24 - 20.5 ranges)= 262.5 energy received with the help of the cool water. warmth lost with the help of the warm metallic = l3.5 gms circumstances (certain warmth metallic) circumstances ( l00- 24 ranges) warmth lost with the help of warm metallic = 262.5 energy = l3.5 gms metallic (sp. warmth metallic) (seventy six ranges) 262.5 energy = 1026 (sp. warmth metallic) sp. warmth metallic = 262.5 energy over 1026 = .26 energy in accordance to gm/degree C in case you want joules, .26 energy circumstances 4.186 joules in accordance to calorie = a million.07 joules/gm/degree. I see that this fee of l.07 joules/gm/degree C is way off the broadcast fee, yet in holding with your lab information, it really is what I got here up ;with.