It's basically a big circle with the bottom part of it shaded in a minor segment. If the maximum depth og the wateri s 2 cm and the radius of the pipee ios 7 cm, find the area shaded. That's a.
b] What is the volume of water in a length of 30 cm?
Think you can handle this question, snickerswaytoomuch? Thanks for the previous question. Anybody's free to answer this question.
2007-05-05 05:29:05 · 3 answers · asked by Avatar Unknown 2 in Science & Mathematics ➔ Mathematics
(a)
Draw a line from the centre of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth. A right-angled triangle is formed. Length of side to the water-surface is 5 cm, the hypot is 7 cm.
What you do now is the following:
Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7)
So θ is approx 44.4°, so the angle subtended at the centre of the circle by the water surface is roughly 88.8°
The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram.
Shaded area ≃ 88.8/360*area of circle - ½*7*7*sin88.8°
= 88.8/360*π*7² - 24.5*sin 88.8°
≃ 13.5 cm²
(using area of ∆ = ½.a.b.sin C for the triangle)
b)
volume of water = cross-sectional area * length
≃ 13.5 * 30 cm³
≃ 404 cm³
2007-05-05 05:34:57 · answer #1 · answered by sumzrfun 3 · 1⤊ 0⤋
Cylindrical Pipe
2016-12-18 11:59:10 · answer #2 · answered by ? 4 · 0⤊ 0⤋
I would guess the answer lies in evaluating a double integral, but I haven't done one in years.
2007-05-05 05:44:16 · answer #3 · answered by night_train_to_memphis 6 · 0⤊ 0⤋