Can someone solve this? It's a Quadratic equation??

Question

(x-a)(x-b) + (x-b)(x-c) + (x-c)(x-a) = 0

Please solve it by using the quadratic formula
which is;
x = -b +- sqroot b^2 - 4ac all over 2(a)

Answer 1

You need to format the original equation so it fits the form used by the quadratic formula. In other words the equation you are solving must fit this form:

ax^2+bx+c=0

For example:

1x^2 - 3x + 2 = 0

x= -(-3) +- sqrt((-3)^2-4*1*2)/(2*1)
which works out to
x=3.5 and x=2.5

In your case you will not be substituting numbers into the quadratic formula (ie. a=1, b=-3, and c=2) as we did in the above example but the letters from your original formula. Good luck solving it!!

Answer 2

if you expand the brackets and add it all up you should get a quadratic like:

3x^2 + x ( -2a -2b-2c) + (ab+bc+ac) = 0

so then use your quadratic formula

A = 3
B = -2a -2b -2c
C = ab + bc + ac

plug it all in and you will have the roots of x

very messy stuff

Answer 3

I think you just factor (x-a)(x-b) and factor (x-b)(x-c) and factor (x-c)(x-a). Then once you have done that add like terms, then use the numbers infront of the terms to do the quadratic.

Answer 4

I'll give you a hint. Factor then solve.

Answer 5

Omfg....learn to do it yourself saggy eye bags!!! lol

Answer 6

i forgot this! but im sure you will get it. just keep reading