hi can anyone find the inverse of f(x)=7+x^3+tan(x(pi)/2) for -1
here x^3 means x raised to the power of 3.
and also find the derivative of f inverse of 7.
thanks
2007-05-05 03:46:50 · 5 answers · asked by MTG G 2 in Science & Mathematics ➔ Mathematics
y=7+x^3+tan(x(pi)/2)
To find the inverse you have to find x=g(y) which is nor possible by algebraics means.
For each y you must solve the equation.The derivative of the inverse function is the inverse of the derivative of y =f(x)
dy/dx = 3x^2+[1+tan^2(pi/2 x)]*pi/2
so dx/dy= 1/(dy/dx)
2007-05-05 03:59:03 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋
Well, finding the inverse seems difficult for me.
Individually, if f(x) = tan (x(pi)/2)
then f inv = x
2007-05-05 04:24:41 · answer #2 · answered by nayanmange 4 · 0⤊ 0⤋
Sorry
2007-05-05 20:35:18 · answer #3 · answered by Anonymous · 0⤊ 0⤋
its difficult
2007-05-05 07:55:27 · answer #4 · answered by exploremyworld 5 · 0⤊ 0⤋
answer is 62 (duh)
2007-05-07 08:30:20 · answer #5 · answered by The Killer Rabbit 1 · 0⤊ 0⤋