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2007-05-05 02:40:16 · 11 answers · asked by Anonymous in Science & Mathematics Other - Science

11 answers

Zero _is_ a number. One of the most important developments in mathematics was the acknowledgement thereof.

0/0 causes problems, since it is meaningless to divide by zero.

Suppose you want to evenly divide a pie between 0 people. How many slices should each of them get?

And if you want patterns to hold, 0/0 should also be 0, since 0/x is 0.

In fact, you can prove anything you want if you let 0/0 have a specific value.

Suppose 0/0 = 1
Then (2 * 0)/0 = 1, since any number times 0 is 0.
But then 2 * 0/0 = 1, so
2 * 1 = 1
2 = 1.

You could "prove" any other goofy thing if you kept all the other laws of math the same, but gave 0/0 a value.

One of the primary areas of study in mathematics is the question of when patterns hold and when they break.

If you haven't been moving at all, but you haven't been measuring for any time, how fast would you say you were going? It could be ANY speed...
This is what Phred said

2007-05-05 02:47:22 · answer #1 · answered by Ultramegathree 2 · 0 0

You can't divide anything by 0, and that includes 0, because the result would have to be a number that, when multiplied by 0, equals 0. But that's just any old number, so your result is indeterminate.
However, if by 0 you mean a very small number very close to 0, such as you might encounter when taking limits (don't worry if that makes no sense) then the normal rules of division apply: any number divided by itself equals 1. But note that e.g. 0.0000002 / 0.0000001 is 2, not 1. Both of the nearly-0 numbers have to be the same is the result is to be 1.

2007-05-05 02:53:27 · answer #2 · answered by rrabbit 4 · 0 0

If you plotted the function x/y = z, you'll see that for different values of y, it's represented by the line x/Y = z. For small positive Y, the slope is positive and steep. For small negative Y, the slope is negative and steep. The limiting case is where Y = 0, where both steep slopes approach a vertical line at (x,y) = (0,0). In other words, the function x/y = z actually takes on all values for z at (0,0), not just "1'".

2007-05-05 04:47:00 · answer #3 · answered by Scythian1950 7 · 0 0

x^o =1
.
x^o = x ^( +1 -1)= x^(+1) x^(-1) = x^(+1) / x^(+1) = 1
.
.

2007-05-05 02:50:16 · answer #4 · answered by Tuncay U 6 · 0 0

0/0 does not equal 1, it is undefined

you cannot divide anything by zero, even zero

http://en.wikipedia.org/wiki/Divide_by_zero

2007-05-05 02:46:44 · answer #5 · answered by Patrick 5 · 0 0

zero is in fact NOT a number, but the absence of intrinsic value, if used in western mathematics.....is just a symbol of emptiness....it will be zero no matter what we do with it..nothing divided by nothing gives you nothing...
However, I understand the mathematical aberration of using a concept (the zero) as a number........
If you divide the mayan zero over mayan zero, you get zero...(because the zero mening nothing as a concept, was the rure in old maths. and other math symbols, more ancient).
Good luck with your grades in the next season,. they can equal the concept (hope not really)

2007-05-07 20:54:31 · answer #6 · answered by Sehr_Klug 50 6 · 0 0

Limit of x/x when x is very close to zero is 1
x/x = 1 for all real x except x=0
division by zero is not defined.
However x can be as close to zero as possible.

2007-05-05 02:46:33 · answer #7 · answered by astrokid 4 · 0 0

My dear you are wrong in fact division to 0 is forbidden!

2007-05-05 18:36:50 · answer #8 · answered by Ahmad k 2 · 0 0

0/0 is not equal to one. it is indetermined.

2007-05-05 02:43:24 · answer #9 · answered by Anonymous · 0 0

It doesn't because you cannot have a zero as a denominator.

2007-05-05 02:53:57 · answer #10 · answered by dwinbaycity 5 · 0 0

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