Came someone do -6^3sqrt(256)+^3sqrt(32)?

Question

Thanks for your help!

the ^3 is this number little number that goes above the square root on the outside, i dont know what its called

Answer 1

I think the answer is... do your own homework you lazy ********.

Answer 2

Repose your question. You have a problem in the way you wrote the problem at the point where I have placed the quotation marks:

-6^3sqrt(256)+"^"3sqrt(32).

It seems as though you intended to raise a number to a power, but forgot to type the number.

Answer 3

By the way for your information:
^y sqrt (x) = x "to the power of" (1/y) = x ^ (1/y)


Legend: cbrt = CubeRoot

-6cbrt(256) + cbrt(32)
=-6 cbrt(2^8) + cbrt(2^5)
= [ -6 * { (2^8) ^ (1/3) } ] + [ { (2^5) ^ (1/3) } ]
= [ -6 * { 2 ^ (8 * 1/3) } ] + [ { 2 ^ (5 * 1/3) } ]
= [ -6 * { 2 ^ (2 + 2/3) } ] + [ { 2 ^ (1 + 2/3) } ]
= [ -6 * { (2 ^ 2) * (2 ^ 2/3) } ] + [ { (2 ^ 1) * (2 ^ 2/3) } ]
= [ { -6 * (2 ^ 2) } * { 2 ^ 2/3 } ] + [ 2 * { 2 ^ 2/3 } ]
= [ -24 * { 2 ^ 2/3 } ] + [ 2 * { 2 ^ 2/3 } ]
= { -24 + 2 } * { 2 ^ 2/3 }
= -22 * { 2 ^ 2/3 }
= -22 * { 2 ^ (2 * 1/3) }
= -22 * { (2^2) ^ 1/3 }
= -22 * { 4 ^ 1/3 }
= -22 cbrt(4)

Answer 4

I think the problem should be like this

-6 (cube root 256) + (cube root of 32)

-6 (cube root 64 x 4) + ( cube root 8 x 4)

-6 (4) (cube root 4) + 2 (cube root 4)

-24 (cube root 4) + 2 (cube root 4)

-22 (cube root 4)