Standard Free energy?

Question

Calculate standard free energy of formation of 1 mol FeS2 at 25 degree's C

Fe(s) + 2S(s) <-------> FeS2(s)

For Fe at 25 degrees C, Delta S = 27.3 J/mol x K
For S at 25 degrees C, Delta S= 31.8 J/mol x K

for FeS2 at 25 degrees
delta S=52.9 J/mol x K and delta H= -178.2 kJ/mol

a–1.9 × 105 J/mol
b–1.8 × 105 J/mol
c–38 J/mol
d–1.7 × 105 J/mol

Answer 1

d