understand?
2007-05-04 19:14:13 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
us the remainder theorem to determine the remainder for each division.
2007-05-04 19:20:06 · update #1
I am still stumped someone please help me
2007-05-04 19:33:51 · update #2
Well, that's not really a question, that's just a function. What do you have to do with that function? Simplify it? Find a limit? Take a derivative? Integral? More is needed.
Your friend,
bigferribunny
2007-05-04 19:18:11 · answer #1 · answered by Bigferribunny 2 · 0⤊ 0⤋
I could tell you what it equals if you divide it.
It's like a normal division, just with x-3 instead of a number.
(x²-5x-9)/(x-3) = x -2
-x²+3x (-x*(x-3))
__-2x-9 (the rest)
__+2x-6 (-(-2*(x-3)))
rest: -15
2007-05-04 19:29:21 · answer #2 · answered by nightgirl1200 4 · 0⤊ 0⤋
. . . . . x - 2
x - 3)x^2 - 5x - 9
. . . . x^2 - 3x
. . . . -----------
. . . . . . . - 2x - 9
. . . . . . . - 2x + 6
. . . . . . . -----------
. . . . . . . . . . . - 15
(x^2 - 5x - 9)/(x - 3) = x - 2 - 15/(x - 3)
2007-05-04 19:34:09 · answer #3 · answered by Helmut 7 · 0⤊ 1⤋