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atoms of naturally occurring sodium?
a. 22.99
b. 1.62 *10^-11
c. 3.73 *10^-10
d. 7.05 *10^-13
e. 2.24 *10^14

2007-05-04 18:52:50 · 2 answers · asked by Mary 1 in Science & Mathematics Chemistry

PLEASE SHOW ALL WORK
AND EXPLANTION

2007-05-04 19:12:31 · update #1

2 answers

1 mole : 6.02x10^23 = x (moles) : 9.76 x 10^12

x = 1.62 x 10^-11 moles Na

1.62 x 10^-11 x 23 g/mol = 3.73 x 10^-10 g Na

2007-05-04 22:54:02 · answer #1 · answered by Anonymous · 0 0

Avagardo told us that 6.02x10^23 atoms weights 23 grams, use a proportion to compute the mass of the given number of atoms.

2007-05-04 18:59:25 · answer #2 · answered by cattbarf 7 · 0 0

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