first make both equations equal to "y"
y = 3x - 9
y = -(1/2) - (3/2)
if you have a graphing calculator, type these equations and check where they intersect on the y-axis. we already know the x-intercept -9 and -3/2, the y-intercept is they "Y" part of the equations
i solved for x got 15/7 and y is -18/7
2007-05-04 18:37:36
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answer #1
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answered by Anonymous
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You have two equations and two variables so it is possible to solve this algebraically. Solve the second equation for x; then substitute the resulting value in for x in the first equation. When y is known, simply place this value in either equation and solve for x.
For example, rearranging the second equation gives x = (y+9)/3. When this is placed in the first equation it becomes (2*(y+9))/3 +4*y = -6. If you simpify and solve you find that y=0. Now place this value for y in either equation and you find x = -3. You can check your answer by placing the values for x and y in both equations and verifying they are correct.
2007-05-04 19:08:54
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answer #2
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answered by RED 4
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x-4y-z=6 2x-y+z=3 ________Adding both equations 3x-5y=9 (3x=9+5y) fixing 2d and third equations (2x-y+z = 3) x -3 = -6x+3y-3z = -9 including the above with the third equatiion -6x+3y-3z = - 9 3x+2y+3z= 16 ______________Adding -3x+5y = 7 or 3x-5y=-7 yet 3x = 9+5y substituting the cost 9+5y-5y = -7 9 = - 7 isn't a probability. for this reason the simultaneous equations are inconsistant and has no answer.
2016-12-05 09:16:39
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answer #3
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answered by ? 4
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2x + 4y = -6
3x - y = 9
a1 = 2, a2 = 3
b1= 4, b2= -1
c1 = -6, c3 = 9
a1/a2 not = to b1/b2
therefore, the two lines intersect
u'll get x = 15/7 and y = -38/7
2007-05-04 18:53:55
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answer #4
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answered by absentmindednik 3
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(1) Solve the first equation for y
2x + 4y = -6
4y = -2x - 6
y = (-1/2)x - (3/2)
(2) Graph the lines.
The y-intercept of the first line is -3/2, and the y-intercept of the second line is -9. The slope of the first line is (-1/2) and the slope of the second line is 3. You'll have to graph them yourself. The solution is the point whether they intersect.
2007-05-04 18:41:56
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answer #5
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answered by mwebbshs 3
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Graphical Solution
To draw the above lines, require 2 points on each line:-
Line 1
2x + 4 y = - 6
(3,-3) and (5,-4) are points on this line.
Line 2
(3,0) , (6,9) are points on this line.
The lines may then be drawn and the point of intersection will be the graphical solution.
2007-05-04 19:25:16
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answer #6
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answered by Como 7
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just draw the equation on a graph and where the two lines intersect that's your answer. First of all solve for y in the first equation, the second one is already done.
2007-05-04 18:38:59
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answer #7
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answered by turnawayandgo 2
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2x+4y=-6----eqn 1
y=3x=-9------eqn 2
substituting value of y in eqn 1
2x+4{3x-9}=-6
14x =-6+36
x =30/14
x =2.14
then y =3[2.14]-9
y =6.42-9
y =-2.58
2007-05-05 00:07:41
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answer #8
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answered by Trika mathematica 1
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b) False
Anything else I can answer for you.
2007-05-04 18:38:10
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answer #9
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answered by David 3
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