..This is a memorized formula
a^3 + b^3 = (a+b) ( a^2 - ab + b^2 )
You are also going to want to know the following:
a^3 - b^3 = (a-b) ( a^2 + ab + b^2 )
a^2 -b^2 = (a-b)(a+b)
a^2 + b^2 cannot be factored, we call it "prime"
2007-05-04 18:27:43
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answer #1
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answered by Anonymous
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Look at what factors these two terms have in common: 3x^3 + 27x Both terms have at least one "x", so you can factor that out as being common to both. So basically we're using the distributive property in reverse: x(3x^2 + 27) Now 27 is a multiple of 3, so we can factor out a 3 from both: 3x(x^2 + 9) It's possible to factor out x^2 + 9 using complex numbers, but I suspect you haven't covered that yet. So we'll just leave this as is.
2016-05-20 23:55:19
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answer #2
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answered by ? 3
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That's the sum of 2 cubes.
The easiest way to remember this is
that a+b is always a factor.
If you forget the second factor, you
can always recover it by long division.
The factors are (a+b)(a²-ab+b²).
2007-05-05 02:17:25
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answer #3
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answered by steiner1745 7
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This is a "standard form" deal, like (a^2-b^2). In this case, the factor is (a+b)(a^2-ab+b^2)
2007-05-04 18:34:11
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answer #4
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answered by cattbarf 7
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a^3 + b^3 = (a + b)(a^2 - ab + b^2)
This is just a formula that I found. I don't know how to prove to you that this is correct.
2007-05-04 18:36:53
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answer #5
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answered by mwebbshs 3
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(a+b)(a^2-ab+b^2)
Example of a formula you should know along with
a^3-b^3;a^2-b^2;a^2+b^2 which cant be factored further.
2007-05-04 19:25:46
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answer #6
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answered by Dave aka Spider Monkey 7
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I know that the question has been correctly answered allready but for future refrence there is a online calculator that will do these questions for you and even explain why.
2007-05-04 18:37:51
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answer #7
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answered by mousehth72 5
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(a+b)*(a^2-ab+b^2)...add and subtract 2(a^2*b+a*b^2) and factorise it...alternatively this is a standard expansion in algebra.
2007-05-04 18:30:38
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answer #8
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answered by fly 2
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does ^ mean power of? like ^2 means squared?cool we are doing polynomials in math today i hate them
2007-05-04 18:29:38
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answer #9
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answered by JamaicaMan 1
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