2007-05-04 10:58:41 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
thank you so much quilashe…
thats exactly what i did i just wanted to make sure that 3080 was teh correct answers.
u r going to get best answer
2007-05-04 11:06:13 · update #1
LCM 3080
10 = 5 X 2
44 = 2X2X11
56 = 7X2X2X2
gathering max number of each factor
three 2s
one 5
one 7
one 11
2X2X2X5X7X11 = 3080
2007-05-04 11:02:22 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Find the prime factors of each:
10= 5*2
44=2*2*11
56=2*2*2*7
So the smallest common factor is 2. If you are looking for the GCF, multiply 2*2*11*5*2*7 = 4*11*10*7 = 44*70 = 3080
2007-05-04 18:04:33 · answer #2 · answered by danjlil_43515 4 · 0⤊ 0⤋
Multiply all three together. Then divide the resultant by two and check that its still a multiple of each of the numbers (by dividing the resultant by each number. If you get a whole number, its a multiple) keep doing this until the test fails.
Answer is 3080
2007-05-04 18:04:16 · answer #3 · answered by Lazer Fazer 2 · 0⤊ 0⤋
10 = 2*5
44 = 2*2*11
56 = 2*2*2*7
so 2*2*2*5*7*11 = 3080
2007-05-04 18:04:22 · answer #4 · answered by hustolemyname 6 · 0⤊ 0⤋
10=2x5
44=2x2x11
56=2x2x2x7
2x2x2x5x7x11=3080
2007-05-04 19:41:39 · answer #5 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
10=2x5
44=11x2x2
56=7x2x2x2
2x2x2x5x11x7= 3080
I think.
2007-05-04 18:05:20 · answer #6 · answered by crazy_lil_penguin 2 · 0⤊ 0⤋