2007-05-04 10:00:29 · 8 answers · asked by jake p 2 in Science & Mathematics ➔ Mathematics
4x(x^2 - 16)
4x *(x-4) * (x+4)
?
2007-05-04 10:05:04 · answer #1 · answered by Anonymous · 1⤊ 1⤋
4x³ - 64x…
Clearly there is a 4 and an x that can be factored out…
4x³ - 64x = 4(x³ - 16x)… factoring out the 4
= 4x(x² - 16)… factoring out the x
The form (a² - b²) should jump out at you at this point. If it doesn’t, memorize this form. You’ll see it a lot. (a² - b²) factors into (a+b)(a-b). Learn it. You’ll use it a lot.
That x² is a perfect square should be obvious. 16 = 4²
4x(x² - 16) = 4x(x + 4)(x – 4).
2007-05-04 17:19:38 · answer #2 · answered by gugliamo00 7 · 1⤊ 0⤋
4x^3-64x = 4x(x^2-16) = 4x(x-4)(x+4)
2007-05-04 17:06:34 · answer #3 · answered by siran357 1 · 0⤊ 0⤋
looks like 4x is a common factor to both terms, so lets pull it out:
4x(x^2 - 16)
Now it should be easier for you to factor:
4x(x + 4)(x - 4)
2007-05-04 17:05:48 · answer #4 · answered by Chad H 3 · 0⤊ 0⤋
move 4x outside the parenthesis:
4x(x^2-16)
and then factor the inside polynomial:
4x(x+4)(x - 4)
2007-05-04 17:05:21 · answer #5 · answered by horrid 3 · 1⤊ 0⤋
4x(x^2-16)
4x(x-4)(x+4)=0
x=0 x=4 x=-4
2007-05-04 17:11:56 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
4x(x+ sqroot 8)(x-sqroot 8)
2007-05-04 17:09:54 · answer #7 · answered by lahomaokie 2 · 0⤊ 0⤋
4x(x^2-8)
2007-05-04 17:04:21 · answer #8 · answered by musics_my_world 2 · 1⤊ 5⤋