2007-05-04 09:18:42 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Rewritten Question = mx +2=4-nx
First step is to put like terms together which includes putting the 2 and the 4 together which is
mx=4-2-nx
2nd step is get x by itself which includes dividing by m on both sides.
mx/m=2-nx/m
last step is to do your calculations right, which is eliminating the m on one side and leave the division on the next side. This is it, it cannot be solved any further
x=2-nx/m
2007-05-04 09:38:40 · answer #1 · answered by katherine 2 · 0⤊ 0⤋
mx + 2 = 4 - nx
mx + nx = 4 -2
(m + n)x = 2
x = 2/(m + n) (with ''m + n'' not equal to 0)
2007-05-04 17:31:30 · answer #2 · answered by frank 7 · 0⤊ 0⤋
Move all x's to one side of the equation:
mx+nx=4-2
Isolate the x
x (m+n)=2
Divide
x=2/(m+n)
2007-05-04 16:22:22 · answer #3 · answered by Dani 2 · 0⤊ 0⤋
mx + nx = 2
(m + n).x = 2
x = 2 / (m + n)
2007-05-04 17:37:46 · answer #4 · answered by Como 7 · 0⤊ 0⤋
x(m+n)=2
x=2/(m+n)
2007-05-04 16:25:20 · answer #5 · answered by hil_gs 1 · 0⤊ 0⤋