How would I factor this?, 3x + x (x + 2)= 0
2007-05-04 08:32:20 · 10 answers · asked by confused 1 in Science & Mathematics ➔ Mathematics
3x + x(x + 2) = 0
3x + x² + 2x = 0
x² + 5x = 0
x(x + 5) = 0
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2007-05-04 09:59:32 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
This is an equation, not an expression. But anyway, you use the distributive property. You get 3x+x^2+2x. You factor out the x's and get 3+x+2=0. Then you go from there and find x to have the value of -5.
2007-05-04 16:49:16 · answer #2 · answered by Danny 4 · 0⤊ 0⤋
multiply out X(X+2) first.
= X^2 + 2X
so the equation now looks like:
3X + X^2 + 2X =0
collect the X terms (3X and 2X) :
X^2 + 5X = 0
bracket the equation:
(X^2 + 5X) = 0
take X out the bracket:
X ( X + 5) = 0
you can then solve:
X= 0 X= -5
2007-05-04 18:03:01 · answer #3 · answered by cheesecheese 3 · 0⤊ 0⤋
3x + x(x + 2) = 0
3x + x^2 +2x = 0
x^2 + 5x = 0
x(x + 5) = 0
Answer : Factors are '' x '' and '' x + 5 ''
2007-05-04 16:16:31 · answer #4 · answered by frank 7 · 0⤊ 0⤋
First distribute.
3x + x^2 + 2x = 0
Combine like terms.
x^2 + 5x = 0
Take out x
x(x+5)
2007-05-04 15:39:57 · answer #5 · answered by delilah 2 · 0⤊ 0⤋
= 3x + x^2 + 2x
= x^2 + 5x
= x(x+5)
2007-05-04 15:37:16 · answer #6 · answered by S17V 4 · 1⤊ 0⤋
x² + 2 x + 3x = 0
x² + 5x = 0
x.(x + 5) = 0
x = 0 , x = - 5
2007-05-04 15:40:06 · answer #7 · answered by Como 7 · 0⤊ 0⤋
Take out the x to get
x(3+x+2) = x(x+5).
2007-05-04 16:49:58 · answer #8 · answered by steiner1745 7 · 0⤊ 0⤋
You can immediately see that both terms of the sum can be divided by x, so you can factor it out... Then you just add together what is left...
2007-05-04 15:38:43 · answer #9 · answered by Daniel B 3 · 0⤊ 0⤋
x^2+5x=x(x+5)
2007-05-04 16:23:16 · answer #10 · answered by rwbblb46 4 · 0⤊ 0⤋