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3 answers

In any aqueous solution, the product of [H+] and [OH-] is always 1E-14, so a simple division gives an [OH-] of 1E-9. By inspection, the pH is 5.

2007-05-04 09:35:16 · answer #1 · answered by Anonymous · 0 0

1 x 10 -9 M

2007-05-04 07:41:55 · answer #2 · answered by Gervald F 7 · 0 0

just apply kw=10^-14=[H+]*[OH-]

make a substitution and:

10^-14=10^-5*x

and x=10^-9

2007-05-04 07:44:11 · answer #3 · answered by Lyla 6 · 0 0

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