2. Copper (I) chloride, CuCL, has Ksp = 1.9 x 10^ -7.calculate the molar solubility of CuCL in pure water.?

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2. Copper (I) chloride, CuCL, has Ksp = 1.9 x 10^ -7.calculate the molar solubility of CuCL in pure water.?

2007-05-04 07:07:49 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

2 answers

Simply take the root of Ksp.

2007-05-04 07:23:29 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋

Equation: Ksp = [Cu+]*[Cl-] You must take into account that the [Cl-] orinating from the KCl = 0.050M. You use the concentration for Cl- in the Ksp equation. 1.0*10^-6 = [Cu+] * 0.050 [Cu+] = (1.0*10^-6)/0.050 [Cu+] = 2*10^-5M The molar solubility of CuCl is 2*10^-5

2016-04-01 08:27:35 · answer #2 · answered by Anonymous · 0⤊ 0⤋