5x-7<2x-1
culd u explain how u do this one please
2007-05-04 06:36:20 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
5x-7+7<2x-1+7
5x<2x+6
5x-2x<2x-2x+6
3x<6
x<2
2007-05-04 07:01:53 · answer #1 · answered by Dave aka Spider Monkey 7 · 1⤊ 0⤋
5x-2x<-1+7 3x<6 x<6/3 x<2
2007-05-04 06:50:20 · answer #2 · answered by dwinbaycity 5 · 0⤊ 0⤋
5x-7<2x-1
first subtract 2x from each side which gives you this: 3x-7<-1
then add 7 to both sides which gives you..3x<6
now divide both sides by 3 which leaves x=2.
hope this helps.
2007-05-04 06:54:56 · answer #3 · answered by Larry 2 · 1⤊ 0⤋
3x-7=-1 subtract 2x from both sides
3x=6 add 7 to both sides
x=2 divide both sides by 3
2007-05-04 06:57:22 · answer #4 · answered by Anonymous · 1⤊ 0⤋