2√3z + 2 - 1 =5. The answer in the book says 7/3, but Im not sure how to get that.?

Answer 1

2√3z + 2 -1 = 5 I'm guessing about ( )
2√(3z+2) -1=5 add 1 to each side
2√(3z+2)=6 divide both sides by 2
√(3z+2)=3 square both sides
3z+2=9 subtract 2 from each side
3z=7 divide both sides by 3
z=7/3

Answer 2

You would get the answer 7/3 if you 3z+2 was all under the square root:

2√(3z+2) = 5+1
2√(3z+2) = 6
√(3z+2) = 6/2
√(3z+2) = 3
* Square both sides to get rid of the square root
3z+2 = 9
3z = 9-2
3z = 7
z = 7/3

Answer 3

Tip
It is a good idea to use brackets in order to prevent misunderstanding of question.

2.√(3z + 2) - 1 = 5
√(3z + 2) = 3
3z + 2 = 9
3z = 7
z = 7 / 3

Answer 4

First of all, I'm going to assume you mean
2√(3z + 2) - 1 =5 and not something like 2(√3z) + 2 - 1 =5

Get the radical by itself. Square both sides to get rid of the radical. Then solve for z:

2√(3z + 2) - 1 =5
2√(3z + 2) = 6
√(3z + 2) = 3
3z + 2 = 9
3z = 7
z = 7/3

Answer 5

You need to show us the same groupings as you were given in the problem.