English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2007-05-04 05:18:24 · 3 answers · asked by Eric M 1 in Science & Mathematics Mathematics

3 answers

I take it you mean √(3x-2) +2 = 0 and not something like
√(3x) - 2 +2 = 0

Get the radical by itself, then square both sides to get rid of the radical. Then solve for x.

√(3x-2) +2 = 0
√(3x-2) = -2
3x - 2 = 4
I'm sure you can take it from there

2007-05-04 05:22:58 · answer #1 · answered by Anonymous · 0 0

√(3x-2) +2 = 0 subtract 2 from each side
√(3x-2)=-2 square both sides
3x-2=4 add 2 to each side
3x=6 divide both sides by 3
x=2

check
√(2*2-2)+2=0
√4+2=0

There is no solution!

2007-05-04 12:27:48 · answer #2 · answered by yupchagee 7 · 0 1

√3x-2 +2 = 0
√3x=0
x=0

2007-05-04 12:24:43 · answer #3 · answered by iyiogrenci 6 · 0 1

fedest.com, questions and answers