How do i do this math problem?

Question

25xsquared minus 4= 0 its about polynomials

Answer 1

It is a difference of squares.

You should know that a^2 - b^2 = (a + b)(a - b)

In this case, a = 5x and b = 2. If you plug those in, you get:

25x^2 - 4 = (5x + 2)(5x - 2) = 0

You also know that if a * b = 0 then a = 0 or b = 0. In this case, you know that either 5x + 2 = 0 or 5x - 2 = 0. Solve for x both times:
5x + 2 = 0
5x = -2
x = -2/5

5x - 2 = 0
5x = 2
x = 2/5

So, x = 2/5 or x = -2/5.

Answer 2

there are couple of options - you can factor or isolate x^2 terms and then square root both sides of the equation.
if we were to factor: 25x^2 - 4 = (5x - 2)(5x + 2)
use zero product property:
5x - 2 = 0 or x = 2/5
5x + 2 = 0 or x = -2/5

OR

25x^2 - 4 = 0
25x^2 = 4
x^2 = 4/25
square rooted: x = +/- 2/5

Answer 3

25x^2 - 4 = 0

I would do the quadratic equation here. 25 is a, b is 0, and c is -4

You'll get two results. Both are acceptable.

Answer 4

25X^2-4 = 0

Add 4 to both sides:

25X^2 = 4

Divide both sides by 25:

x^2 = 4/25

Take Square Root of both sides:

X = +2/5, -2/5

Answer 5

25x² - 4 = 0
(5x - 2).(5x + 2) = 0
x = 2 / 5 , x = - 5 / 2

Answer 6

25x² - 4 = 0
(5x - 2)(5x + 2) = 0

5x = ±2
x = ±(2/5)

Answer 7

factor as difference of two squares
x^2-y^2 = (x+y)(x-y) so

25x^2-2^2 = (5x+2)(5x-2)