All quadractic equations may be solved by completeing the square? True or False?
I think this is true becuase all equations can be solved with either the quadratic or completing the square method..is this right?
2007-05-04 04:00:52 · 6 answers · asked by confused 1 in Science & Mathematics ➔ Mathematics
yes, BUT you won't have whole numbers sometimes, you could have decimals so long that only computers may be able to solve it.
2007-05-04 04:08:55 · answer #1 · answered by gregthedesigner 5 · 0⤊ 0⤋
nicely-known kind is Ax^2 + Bx + C = 0 A = 3 B = -8 C = 4 seek for 2 numbers that multiply to AC upload upload as much as B. AC = ability A x C 3*4 = 12 so seek for 2 numbers that multiply to twelve and upload to -8 -2 * -6 = 12 -2 + (-6) = -8 so the two numbers are -2 and -6 rather of write 3x^2 - 8x + 4 = 0, use the two numbers you basically stumbled on and write the equation like this: 3x^2 -2x - 6x + 4 = 0. ( once you combine lerms do you notice -2x - 6x = -8x ? ) next step is element by communities (3x^2 - 2x) + (-2x + 4) = 0 take out x and -2 x(3x - 2) + -2(x-2) = 0 take out 3x-2 (x-2) (3x-2) = 0 so x = 2 or 2/3. wish this facilitates
2016-12-10 19:06:57 · answer #2 · answered by ? 4 · 0⤊ 0⤋
True
2007-05-04 04:09:39 · answer #3 · answered by bignose68 4 · 0⤊ 0⤋
Ya correct
2007-05-04 05:00:21 · answer #4 · answered by tamaki_teoh 1 · 0⤊ 0⤋
Yes i think it's true too.
2007-05-04 04:39:05 · answer #5 · answered by Anonymous · 0⤊ 0⤋
True
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2007-05-04 04:26:34 · answer #6 · answered by SAMUEL D 7 · 0⤊ 0⤋