solve for y in the second equation: y = 11-3x.
substitute this value into the first equation: x + (11-3x) = 3
Solve for x and you get x = 4
than plug that back in to either equation to get y = -1.
Hope this helps
2007-05-04 02:40:38
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answer #1
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answered by engineeringguru 2
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x= 4
y = -1
2007-05-04 20:52:08
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answer #2
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answered by Vatsal S 2
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x+y=3 --------- (1)
3x+y=11-------(2)
(1) - (2) :-
x + y = 3
-(3x + y = 11)
-2x=-8
x=4
when x=4
therefore,
4 + y = 3
y = 3 - 4
y = -1
therefore, the value of x = 4 and value of y = -1
2007-05-04 03:46:49
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answer #3
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answered by lkl916 1
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i'm getting tried of training you attempt e book author a thanks to do the topic matters in you books, purely supply up... x-y=11 3x+10y=-6 sub for x so x=11+y 3(11+y)+10y=-6 33+3y+10y=-6 33+13y=-6 upload or subtract your 33 now it really is (subtract) -6-33=-39 13y=-39 now div out 13 equaks to 13/-39 (13+13=26 26+13=39 so 3 circumstances) so 13 bypass into 39) 3 circumstances that can make it y=-3 9since we had a neg. signal... now bypass lower back by and sparkling up for x an similar way (maximum the time the answer will be an similar, yet examine in case its no longer a regulation they should be an similar) good luck; did you examine my funny tale its equivalent no longer equaks gosh i'm so humorous. -edit- there have been some spelling blunders. it type of not undemanding to do English and math mutually... ok positive, I had 13 as an answer I purely were given cot up in writing each and every thing. its -3 for y you could attempt something else.
2016-11-25 01:37:31
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answer #4
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answered by bebout 4
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x+y=3 --------(1)
3x+y=11 --------------(2)
we have the coefficients of y equal. So, we can subtract equations
3x+y=11
but we want to subtract. Hence, -(x+y=3)
-x-y=-3
Now subtract
3x+y=11
-x -y=-3
2x =8
x=8/2
x=4 ---------------value(1)
Substitute x=4 in equation (1)
x+y=3
4+y=3
y=3-4
y=(-1) ----------------value (2)
Ans. The solution of the equations is x=4 and y=(-1)
2007-05-04 18:47:30
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answer #5
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answered by Krishna 2
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I) (x+ y = 3
II) (3x + y = 11
I) x = 3 - y
II) 3(3 - y) + y = 11
9 - 3y + y = 11
-2y = 11 - 9
-2y = 2
y = 2 : -2
y = -1
x = 3 - y
x = 3 - (-1)
x = 4
Solution: {x and y belong to R| x = 4 and y = -1}
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2007-05-04 03:07:22
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answer #6
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answered by aeiou 7
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x+y=3 -(1)
3x+y=11 -(2)
multiplying (1) by 3 we get
3x+3y=9 -(3)
subtracting (3) by (2),
3x+y=11
-3x+3y=9
-------------
-2y=2
therefore,y= -1
substituting y= -1 in equation (1) we get,
x+(-)1=3
x=3+1
x=4
therefore x=4 & y=(-1)
2007-05-04 03:08:53
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answer #7
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answered by unknown 2
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x+y = 3 ----------1
3x+ y=11--------2
subtractig the equation 1 from eq. 2
2x = 8
x =4
substituting the value of x in eq1
4+y=3
y= 3 - 4 = -1
2007-05-04 05:31:57
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answer #8
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answered by Pranil 7
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Just subtract the first equation from the second
to get 2x = 8
x = 4
y = -1
2007-05-04 02:52:32
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answer #9
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answered by steiner1745 7
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x + y = 3
y = 3 - x ______ (1)
Sub. (1) into (2)
3x + y = 11_______ (2)
3x + (3 - x) = 11
2x = 8
x = 4
Sub x = 4 into (1)
4 + y = 3
y = -1
2007-05-04 03:01:27
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answer #10
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answered by Tsuki 2
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