An ideal transformer connects a 120-V source to a 12-V, 1-A load. The secondary has 90 turns. Determine the following:
-A) Number of turns in the Primary
-B) Source Current
2007-05-04 00:48:53 · 5 answers · asked by ? 2 in Science & Mathematics ➔ Physics
Turns ratio =120 /12 =10:1
Secondary =90 turns
Therefore primary = 900 turns
Current ratio is 1:10
Therefore primary current = 0.1 A
2007-05-04 01:01:36 · answer #1 · answered by lunchtime_browser 7 · 0⤊ 0⤋
A)
120/12=N/90
N=900
B)
i/1=900/90
i=10A
2007-05-04 00:53:07 · answer #2 · answered by Anonymous · 1⤊ 0⤋
The secondary voltage is 360 volts. because the transformer is theory the wide-spread ability and the secondary ability are an similar. Isec=360/Z2, so the plain ability is 360*360/Z2.
2016-11-25 01:26:35 · answer #3 · answered by Anonymous · 0⤊ 0⤋
A. 900 turns
B. 100 mA
C. You really need to start studying ☺
Doug
2007-05-04 01:36:25 · answer #4 · answered by doug_donaghue 7 · 0⤊ 0⤋
God bless you
2007-05-04 00:58:59 · answer #5 · answered by Ased Kooshan 3 · 0⤊ 0⤋