English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

The value of cos(-(pi/2))

can you help me solve this please!

2007-05-03 22:08:57 · 9 answers · asked by w s 3 in Science & Mathematics Mathematics

the question is The value of cos(-(pi/2)) is:

2007-05-03 22:09:37 · update #1

9 answers

cos(-(pi/2))
=cos-90
=cos90
=1

2007-05-03 22:15:03 · answer #1 · answered by Vikram N 1 · 0 0

hi....
the value of cos(-(pi/2))
if the (-pi/2) is degree then the value is: 0.999624
if the (-pi/2) is gradian then the value is: 0.999696
if the (-pi/2) is radian then the value is: 0.00000
have nice day

2007-05-04 05:21:39 · answer #2 · answered by Siavash 1 · 0 0

When angles are given in multiples of pi then they are in RADIANS, NOT DEGREES.

To convert, multiply by (180/pi)

(Although your calculator will do the problem in radians anyway if you switch it from DEG mode to RAD mode)

So -pi/2 radians is -90 degrees.

So cos(-(pi/2)) RADIANS = cos(-90) DEGREES

= 0

2007-05-04 05:20:21 · answer #3 · answered by joncummins1968 4 · 0 0

cos (-(pi/2)) = 0

this is because when you graph (-pi/2) on the cartesian plane, it falls on the negative y-axis

since it is vertical, its x-component is 0

cos is a function that can be imagined as representing the x-component of a vector =)

2007-05-04 05:32:45 · answer #4 · answered by !_! 2 · 0 0

0 cos(270 degrees)

2007-05-04 05:23:36 · answer #5 · answered by blahman 2 · 0 0

Ans : 0

cos( -(180/2)) = cos(-90) = - cos(90) = 0 !!!!!

2007-05-04 05:19:19 · answer #6 · answered by Kumar 3 · 0 0

cos(-pi/2)=cos(pi/2)=0
cos(-x)=cos(x)

2007-05-04 05:30:12 · answer #7 · answered by Niranjan 1 · 0 0

cos(-(Pi/2)) = 0

- - - - - - -s-

2007-05-04 09:08:36 · answer #8 · answered by SAMUEL D 7 · 0 0

0.9996242169 (to 10dp)

2007-05-04 05:12:47 · answer #9 · answered by Doctor Q 6 · 0 0

fedest.com, questions and answers