(1/(x+1))-((x+2)/(x^2-1))
can anybody solve this?
2007-05-03 21:37:47 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(1/(x + 1)) - ((x + 2)/(x^2 - 1)) =
(1 / (x + 1)) - ((x + 2) / (x + 1) (x - 1)) =
((x - 1) / (x + 1)(x - 1)) - ((x + 2) / (x + 1) (x - 1) ) =
(x - 1 - x - 2) / ( (x + 1) (x - 1) ) =
- 3 / ( (x + 1) (x - 1) )
2007-05-03 21:51:00 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
3
2007-05-04 04:45:37 · answer #2 · answered by Anonymous · 0⤊ 0⤋
[1/(x+1)] - [(x+2)/(x^2-1)]
= [(x-1)/(x+1)(x-1)] - [(x+2)/(x^2-1)]
= [(x-1)/(x^2-1)] - [(x+2)/(x^2-1)]
= [(x-1)-(x+2)]/(x^2-1)
= (x-1-x-2)/(x^2-1)
= -3/(x^2-1)
2007-05-04 04:51:42 · answer #3 · answered by ~ 1 · 0⤊ 0⤋
NO... There's no equal sign. Hence, it's not an equation.
2007-05-04 04:45:55 · answer #4 · answered by Afternoon Delight 4 · 0⤊ 0⤋