sketch y=1/4(x-2)^3+3.?

Question

answer my friend

Answer 1

y'=3/4 (x-2)^2

y''=3/2 (x-2)

if y"=0
then x=2

the inflection point is (2,3)

The curve passes through the points
(0,1), (2,3)

it is continuous curve