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Determine if the equations are perpendicular.

Y= - 0.0625x + 11
Y – 16x = -14

What is the slope of the line Y= - 0.0625x + 11? ______

What is the slope of the line Y – 16x = -14? _____

Are the graphs of the given equations perpendicular? ___

2007-05-03 20:02:11 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

To find the slope of the line, write the equation in form y = mx + b, then the slope is m.

y = -0.0625x + 11: the slope is -0.0625
y - 16x = -14: rewrite as y = 16x - 14, the slope is 16

The lines are perpendicular if the slopes multiply to -1.
16*(-0.0625) = -1, so the lines are perpendicular.

2007-05-03 20:07:27 · answer #1 · answered by Scarlet Manuka 7 · 0 0

we know that equation of slope is y=mx+c

where m=slope of line

y= -0.0625x+11 than

slope of line y= -0.0625

second y-16x= -14

we can write as y=16x-14

than slope of line y= 16

the product of both slope is (equal to) 16*(-0.0625)= -1 so line r

perpendicular.

2007-05-04 03:59:35 · answer #2 · answered by ANJU R 2 · 0 0

slope of line 1 is = -0.0625
slope of line 2 is = 16
yes the lines are perpendicular since the product of their slopes is -1
that is tan(angle)= -1 that is angle = 90 degrees

2007-05-04 03:12:14 · answer #3 · answered by Anonymous · 0 0

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