a. NaCl ,
b. H2O,
c. NaOH,
d. C8H18 (octane)
e. none of them
Checked everywhere in my text but cant figure it out still, arghhh!! And if anyone knows the answer can you tell me why as i would love to know as this question has me beat, for now.
Thanks heaps guys
2007-05-03 19:29:41 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
it'll be octane.
The reason behind this is that all the other mentioned substances are polar & had a tendency to dissolve in polar solvents. Their dissolution occurs either due to dipole-dipole attraction or H-bonding. But non-polar solutes do not generally dissolve in polar solvents because they lack the polar nature in their molecule. They are generally soluble in non-polar solvents. CCl4 & octane both being non-polar, octane is likely to be soluble in CCl4.
2007-05-03 20:13:42 · answer #1 · answered by s0u1 reaver 5 · 0⤊ 0⤋
CCl4 is a non-polar solvent, meaning in straight forward terms hydrophobic or water-hating compounds would be dissolved in it. for this reason, the final answer would be C8H18, that's octane and a hydrocarbon.
2016-12-28 11:39:48 · answer #2 · answered by douse 3 · 0⤊ 0⤋
Octane, because, like CCl4, it is non-polar.
2007-05-03 19:32:52 · answer #3 · answered by Gervald F 7 · 0⤊ 0⤋
it is maybe octane
2007-05-03 21:03:34 · answer #4 · answered by jetboy861 3 · 0⤊ 0⤋