Find the equation of a line contain the given point and having the given slope.
(4,4), m= 7/8
the equation is y= __ x + ___
2007-05-03 17:39:22 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
For this you use the equation Y-Y1=M(X-X1) where X1 and Y1 are the points and M is the slope so you get the equation:
Y-4=7/8(X-4)
Simplifying gives you the equation:
Y=7/8X+1/2
2007-05-03 17:44:40 · answer #1 · answered by deathwatchmjc 2 · 0⤊ 0⤋
That is easy, y=mx+b y=7/8x+b
Substitute (4,4) fot y and x 4=7/8(4)+B
4=3+B
B=1
final answer- y=7/8x+1
2007-05-03 17:49:33 · answer #2 · answered by wp_snowboarder 2 · 0⤊ 0⤋
The eqn is (y-y1)=m(x-x1)
Your Answer is y-4 = 7/8(x-4)
8y-32 = 7(x-4)
= 7x-28
therefore, the reqd eqn is 7x-8y+4 = 0
2007-05-03 17:51:58 · answer #3 · answered by TAMIZHAN 1 · 0⤊ 0⤋
y-4 = (7/8) (x-4) which becomes
y = (7/8) (x-4) + 4 which simplifies to
y = (7/8) (x) + 1/2
2007-05-03 17:45:05 · answer #4 · answered by answerING 6 · 0⤊ 0⤋
y-4=7/8(x-4)
8y-32=7x-28
8y=7x-28+32
8y=7x+4
y=7/8 x + 1/2
2007-05-03 17:47:00 · answer #5 · answered by iyiogrenci 6 · 0⤊ 0⤋
its always y=mx+b, m=slope and b=initial position so
y=7/8x+4
2007-05-03 17:42:31 · answer #6 · answered by Daveman 2 · 0⤊ 0⤋