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2007-05-03 17:27:23 · 3 answers · asked by ashleyjohn18 1 in Science & Mathematics Mathematics

3 answers

3x^3-4x^2+8x+C where C is a constant

2007-05-03 17:31:48 · answer #1 · answered by Scott H 3 · 0 0

I think this is what we called an indefinite integral in the old days. The operation yields (opposite of the power rule for derivitives)
3x^3 - 4x^2 + 8x + c, where c is an indefinite constant which requires other info to evaluate.

2007-05-04 00:32:49 · answer #2 · answered by cattbarf 7 · 0 0

3x^3-4x^2+8x+C

2007-05-04 00:33:20 · answer #3 · answered by iyiogrenci 6 · 0 0

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