a sample of a gas in a cylindrical chamber w/ a movable piston occupied a volume of 1.40 liters when the pressure ws 762 torr and the temp. was 26.9 deg C. The volume of the system was readhusted to 0.150L by moving the piston. What was the pressure on the surface of the piston, in atmospheres, by the gas if the temperature remained constant?
I keep getting this wrong, I think I'm missing something
2007-05-03 16:15:37 · 2 answers · asked by A 3 in Science & Mathematics ➔ Chemistry
This is Boyle's Law P1V1 = P2V2
You have V1 and V2. You have P1. Just plug in and solve for P2.
However, the P2 will be in torr (mm of Hg) You must convert to atmospheres by dividing by 760 torr / atm.
2007-05-03 16:19:17 · answer #1 · answered by reb1240 7 · 0⤊ 0⤋
STATE 1
P1V1=nRT
STATE 2
P2V2=nRT
The number of moles stays the same, gas constant and temp too...so...
p1v1=p2v2
if you increase the volume the pressure decreases
2007-05-03 23:36:48 · answer #2 · answered by kman 1 · 0⤊ 0⤋