A colorblind male has children with a female that is a carrier for colorblindness.?

Question

What is the genotype of the mother?
What is the genotype of the father?
Using a Punnett square, determine the population of the F1 generation.
What percentage of their boys will be colorblind?
What percentage of their girls will be colorblind?

Answer 1

ok, so the mother? she is, as i assume, not colorblind.

C= able to see color
c= colorblind

so the genotype of the father would be XcY, since colorblindness only occurs on the x chromosome.

the genotype of the mother would be XCXc, meanign that she's a carrier, even though she can see all right.

and when you put that into a punnet square (XC and Xc for mom.....and for dad, Xc and Y), you get XCXc, XcXc, XCY, and XcY.

therefore, for daughters, one color blind and one not colorblind (but is a carrier). and for sons, one will be color blind and the other one will not be.

This is why boys have a higher percentage of being color blind, because if they are a carrier, then they are colorblind, while girls can be carriers, but have a backup and still see all right.

Answer 2

you be conscious of that colorblindness is basically on x chromosomes, suited? so C= colour and c= colorblind i'm assuming that the mum can see properly, yet is basically a service, suited? so mom's genotype: XCXc (the dominant trait regulations over the recessive trait) and the father's genotype: XCY (so no longer a service and not colorbind) you place that right into a punnet sq. (mom is XC and Xc, father is XC and Y) youngster's genotypes are : XCXC, XcXC, XCY, and XcY so not one of the ladies are colorblind. and 50 p.c. of boys would be colorblind and 50 p.c. won't.

Answer 3

Red-green colorblindness is recessive and on the X-chromosome.

Mom must be XB Xb to be a carrier.
Dad must be Xb Y to have colorblindness.

Gametes are:
XB and Xb for Mom -- put these on the left side of the Punnett square.
Xb and Y for Dad -- put these on the top of the Punnett square.

First row of boxes in the Punnett square is XB Xb and XB Y.
Second row of boxes is Xb Xb and Xb Y.

Of the two possibilities for boys, one is expected to be colorblind. 1/2=50%
Of the two possibilities for girls, one is expected to be colorblind. 1/2=50%