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how would i find s sub 25 for each of these arithmetic series?

25+24+23+22+...

2007-05-03 12:46:50 · 1 answers · asked by =] 1 in Science & Mathematics ➔ Chemistry

1 answers

S1 = 1*(25-(1-1)/2)
S2 = 2*(25-(2-1)/2)
S3 = 3*(25-(3-1)/2)
Sn = n*(25-(n-1)/2)
S25 = 25*(25-(25-1)/2) = 325

2007-05-04 05:20:58 · answer #1 · answered by kirchwey 7 · 0⤊ 0⤋

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