chem help please?

0 ⤊

what do you get for the answer

Calculate the molar solubility of PbS (Ksp = 9.04 10-29).

i got 3.562154989E-10 why is it wrong.

2007-05-03 09:15:31 · 3 answers · asked by Krazyk78 1 in Science & Mathematics ➔ Chemistry

let x = molar solubility = [Pb] = [S] = 9.04 *10^-29

Ksp = [Pb][S] = x^2 = 9.04 *10^-29

x = 9.51 * 10^-15 M

2007-05-03 09:23:41 · answer #1 · answered by Dr Dave P 7 · 0⤊ 0⤋

PbS is diatomic. So the formula for its solubility is:
Ksp = (S)^2
9.04 x 10^-29 = S^2
(Take the square root to get S)

S = 9.51 x 10^-15

2007-05-03 16:25:43 · answer #2 · answered by ? 4 · 0⤊ 0⤋

Just take the root of the Ksp. I got 9.51 x 10 -15.

2007-05-03 16:24:55 · answer #3 · answered by Gervald F 7 · 0⤊ 0⤋