OPEN ENDED, MATH .. multilple choice?

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OPEN ENDED, MATH .. multilple choice?

If the password to get into a garage is four numbers long, and you can only use the numbers one through nine, how many different passwords would there be?
3024
6561
36
4

2007-05-03 08:40:26 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

5 answers

9^4 = 6561

2007-05-03 08:45:31 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋

9 ^4 = 6561

2007-05-03 15:45:42 · answer #2 · answered by Baysoc23 5 · 0⤊ 0⤋

There would be 9*9*9*9 or 6561 different passwords,
by the fundamental principle of counting.

2007-05-03 15:45:54 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋

9*8*7*6=3024 if repeating is not allowed;
9^4=6561 if repeating is allowed.

2007-05-03 15:47:46 · answer #4 · answered by bruinfan 7 · 0⤊ 0⤋

6561

2007-05-03 15:48:39 · answer #5 · answered by HP Fan 2 · 0⤊ 0⤋