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4 answers

get a jar the same size, and buy some bags of the same size jelly beans.
From there figure it out.

2007-05-03 08:43:12 · answer #1 · answered by unan1m0us 5 · 0 0

-----Jars are usually of a standard size. Get a jar of the same size and determine the volume of jelly beans by filling it with water to about the same level as the jelly beans. Measuring the water will give you the volume of the jelly beans in the jar. Then determine the volume of the same kind of jelly bean; perhaps the label on the jelly bean package will help, or you can determine the volume of water the jelly bean replaces by pushing it under water and seeing how much the water rises above the starting mark in some kind of graduated cylinder when the jelly bean is fully submerged. I am assuming you are looking at the jelly bean jar through a window. If you can pick up the jar, you can weigh it, then weigh an empty jar of the same size, and then weigh one jelly bean. Dividing the weight of the one jelly bean into the difference between the full and empty jar will give you the number of jelly beans in the jar. You can also count a column of jelly beans up the front of the jar, and a row of jelly beans along the side of the jar, and multiply. Or you can count a column of jelly beans up the front, and a circumference of jelly beans around the jar, divide the circumference by four to give a "row", then multiply that "row" by the column height to give the number of jelly beans. If you do more than one method, you can then average the results, which should give a more accurate result ---Jim

2007-05-03 16:13:49 · answer #2 · answered by James M 4 · 1 0

Figure it out like the area of a cylinder, then count the number it takes to fill the bottom of the jar and multiple by the area and it should come out pretty close.

Hope this helps.

2007-05-03 15:43:26 · answer #3 · answered by rich c 3 · 0 0

yes u count the rows vertical and hor and then multiply them by each other or coutn the number in a row and estemte how many rows there are

2007-05-03 15:42:49 · answer #4 · answered by tricklamb 2 · 0 0

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