How many acres of surface area deos the reservoir occupy ?
2007-05-03 07:47:21 · 7 answers · asked by michael g 1 in Science & Mathematics ➔ Geography
850 times 470 equals 399500 square feet
divide by 43560 SF per acre
9.17 acres
since it is 10 feet deep it is 91.7 acre feet of water
2007-05-03 07:56:41 · answer #1 · answered by iam2inthis 4 · 0⤊ 0⤋
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2016-04-01 07:00:49 · answer #2 · answered by Anonymous · 0⤊ 0⤋
850 x 470 = 399,500ft²
1 acre = 43,560ft²
Surface area = 399,500 ÷ 43,560 = 9.171 acres.
2007-05-03 10:05:13 · answer #3 · answered by Norrie 7 · 0⤊ 0⤋
9.171221 acres
just over 9 acres, approximately.
(1 acre = 43560.17 square feet)
.
2007-05-03 07:54:46 · answer #4 · answered by tlbs101 7 · 0⤊ 0⤋
9.17 acres - the 10 feet deep part is irrelevant
2007-05-03 07:55:09 · answer #5 · answered by Anonymous · 0⤊ 0⤋
850X470=399,500/43,560=9.17acres
depth is irrelevant, acres are a 2 dimensional measurement
if you are talking volume as in ft. acres it would be
91.7 ft acres
2007-05-03 08:02:58 · answer #6 · answered by Anonymous · 1⤊ 0⤋
One acre = 208.71 ft x 208.71 ft = 43560 ft2
850 / 208.71 = 4.07
470 / 208.71 = 2.25
Surface of reservoir = 4.07 * 2.25 = 9.16 acres
(depth is not relevant to surface area calculation)
2007-05-03 09:52:08 · answer #7 · answered by CanTexan 6 · 0⤊ 0⤋