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Find the mode of this set of data: 3, 3, 5, 3, 3, 7, 300, 5, 3, 3?
300

3

33.5

5

2007-05-03 07:17:46 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

The mode is the value with the most entries which in this case is 3

2007-05-03 07:40:52 · answer #1 · answered by dogsafire 7 · 0 0

3

2007-05-03 07:45:28 · answer #2 · answered by Rana 1 · 0 0

3

2007-05-03 07:29:57 · answer #3 · answered by B S 1 · 0 0

3

2007-05-03 07:25:41 · answer #4 · answered by nadia s 2 · 0 0

9.seventy 5 mph rationalization: that's a tricky question given which you're no longer given the present, which for sure slows the boat on the 1st leg and speeds it up on the 2d. the main right that's that the present is a relentless (if it weren't, we could no longer resolve the concern). that's measured in miles in step with hour and on the upstream holiday it impacts the boat for 4 hours, yet on the downstream holiday, in basic terms for 2.5 hours. So the present certainly has greater result on the 1st component of the holiday than the 2d. that's why you won't be able to easily average the holiday (the boat coated 60 miles - 30 plus 30 - in 6.5 hours - 4 plus 2.5) right this is how I solved it: enable x = the cost of the boat in nonetheless water enable y = the cost of the present 4(x-y)=30 4 hours of boat velocity minus present day is 30 miles 2.5(x+y)=30 2.5 hours boat velocity plus present day is 30 miles making use of the 1st equation, resolve for y in terms of x. 4(x-y)=30 4x-4y=30 -4y=30-4x y=x-7.5 now insert the recent description of y into the 2d equation 2.5(x+y)=30 will become 2.5(x+x-7.5)=30 now resolve for x 2.5(x+x-7.5)=30 2.5(2x-7.5)=30 5x-18.seventy 5=30 5x=40 8.seventy 5 x=9.seventy 5 the cost of the boat in nonetheless water is 9.seventy 5 mph

2017-01-09 09:59:05 · answer #5 · answered by Anonymous · 0 0

i hope you are kidding

b) 3

2007-05-03 07:28:34 · answer #6 · answered by Anonymous · 0 0

3

Maybe you need to learn your definitions

2007-05-03 07:50:15 · answer #7 · answered by junkgolf 2 · 0 0

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