With the best will in the world, you yourself can't help her. You can be there to support her, but eating disorders are complex and difficult to treat. If you can get your friend even to see that there's a problem you will be doing her a service.
Getting her to professional help would be the next step.
You're obviously a caring soul, be careful not to get drawn in too far; in the long run it is her problem.
Jon C
2007-05-03 08:02:37
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answer #1
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answered by Anonymous
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Sigh...that's a real toughie. I say tell someone like a school counselor; someone that can steer her in the right direction. Or bring it up to her parents. Sure, you may be accused of being a rat, but at least you'll be getting her help. She'll thank you one day.
2007-05-03 14:09:43
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answer #2
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answered by vengeancethiswaycomes 1
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i had a frined who also was anorexic. the best thing that yuo can do is always be there for her (which i'm sure oyu would anyway).
i think you should possibly try speaking to an adult or counsellor about it but i'm not overly sure.
i really hope she stops soon, good luck, x
2007-05-03 14:05:43
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answer #3
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answered by FreakGirl 5
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get her to a doctor asap.. she needs to be checked to make sure she isn't malnourished and she needs to see a counselor....best thing you can do for her is get her help.. this CAN be life threatening.. it's not always.. but it can be... do the right thing.. tell her parents.. tell a school counselor.. tell whoever.. you may lose a friend.. but you'll save a life.. and what is more important?
2007-05-03 14:21:46
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answer #4
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answered by pip 7
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both conditions are symptomatic of very low self esteem and control issues in the home
she should have a therapist look at her
referal from the doctorwould help her
you cant help her hon
only someonewhose trained can
but thanks for caring
2007-05-03 14:05:59
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answer #5
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answered by ~*tigger*~ ** 7
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She needs professional help. Try and persuade her
2007-05-03 14:03:58
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answer #6
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answered by Anonymous
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hold hair back so it doesnt fall in the toilet water
2007-05-03 14:09:43
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answer #7
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answered by Anonymous
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