Trig question.. Thankyou for taking the time to help me solve this!! I use it as notes to study from?

Question

Find the area of triangle ABC

Angle A= 33 deg 20', Angle C= 98 deg 40' , and side b =22.5 ft

a). 185 ft ^2
b). 375 ft ^2
c). 370 ft ^2
d). 180 ft ^2

Answer 1

Area = (1/2)bh
Area = (1/2)basinC
Area = (1/2)b^2sinAsinC/sinB
B = 180 - A - C = 48°
Area = (1/2) (22.5)^2 (0.5495090) (0.9885817) / (0.7431448)

Area = 185.0329 ft^2 ≈ 185 ft^2