720
(= 6!)
This is because you can choose any of the 6 books to put on the shelf first.
Then you have 5 books left to arrange and you can choose any of them to put second. Then 4, 3, 2 and finally there's only one book left
so the number of ways is
6! = 6·5·4·3·2·1 = 720
Hope this helps.
2007-05-03 05:49:43
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answer #1
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answered by M 6
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6 X 5 X 4 X 2 X 1 = 720 or in a short way, 6! = 720
2007-05-03 05:52:39
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answer #2
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answered by Swamy 7
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the ways that you can arrange 6 books on a shelve is 6! = 720
Reasoning behind this is
for the first empty space : there are 6 possible books you can put in there
2nd empty space, u can only choose out of 5 books to place there (since u've already placed one book in the first slot)
continue using this logic with the remaining books and you will get 6 * 5 * 4 * 3 * 2 * 1 = 6! = 720
2007-05-03 05:54:27
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answer #3
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answered by kkoh 2
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Since the books are finite objects and cannot be used twice, the answer is: !6 (6 factorial)
6*5*4*3*2*1 = 720
This is the total number of combinations you can have on a shelf of 6 books.
If it was TITLES (meaning you could have 6 books with the same title) it would be 6^6=46656
2007-05-03 05:53:44
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answer #4
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answered by MrDave2176 3
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Starting with six books, you can pick any of the six to be on the left, any of the remaining five to be next to it, any of the remaining four to be next to that, and so on, so the number of possibilities is 6 x 5 x 4 x 3 x 2 x 1, or 6! (six factorial), which is 720.
2007-05-03 05:52:12
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answer #5
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answered by Anonymous
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That's 6! = 720.
It's the number of permutations of 6 different objects.
2007-05-03 05:55:43
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answer #6
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answered by steiner1745 7
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6*5*4*3*2*1=720
2007-05-03 05:51:43
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answer #7
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answered by Anonymous
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6!= 6x5x4x3x2x1= 720 different ways
2007-05-03 05:53:07
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answer #8
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answered by Birim 3
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12 books would be 479 millio......better just plan on spending a whole afternoon in your library to check out all these arrangements.
2007-05-03 07:31:27
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answer #9
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answered by Anonymous
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