Find the length of the following segment created by these pairs of endpoints: (3, 6), (2, 1)
3
1
5
2
2007-05-03 03:51:39 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Try this website it is very helpful
http://www.purplemath.com/modules/distform.htm
2007-05-03 04:00:05 · answer #1 · answered by franklino 4 · 0⤊ 0⤋
it appears to be none of the answers you have provided. By using the Pythagorean formuls (a^2 + b^2 = c^2), the two perpendicular sides of the triangle created are lengths of 1 and 5. So, the hypotenuse (which you're trying to determine the length of) is the square root of 26, or 5 and change.
2007-05-03 10:59:40 · answer #2 · answered by bwn000 1 · 0⤊ 1⤋
The length of the segment is the distance
between the points.
The distance formula gives
â(x_2 - x_1)² + (y_2 - y_1)² = â1+25= â26.
So none of your choices is correct.
2007-05-03 11:40:18 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
To find the distance, you don't use the freaking slope formula (y2-y1) / (x2-x1), morons. you use the distance formula
The Square Root of [(x1 - x2)^2 + (y1 - y2)^2] = Radical 26 which is about 5. Godddddddd........
2007-05-03 11:04:38 · answer #4 · answered by You Are a MORON!!!!!!shift+one1! 2 · 0⤊ 1⤋
the answer is the square root of 26. So none of the choices is right
2007-05-03 10:56:53 · answer #5 · answered by Rich B4 1 · 0⤊ 1⤋
5
y1-y2
x1-x2= 5/1=5
2007-05-03 11:03:11 · answer #6 · answered by emyof09 1 · 0⤊ 1⤋
sq.root 26
2007-05-03 10:56:29 · answer #7 · answered by nelaq 4 · 0⤊ 1⤋
5.09 would be the answer...so i guess 5 is rite
2007-05-03 10:59:10 · answer #8 · answered by crazy_music_friends_life 2 · 0⤊ 1⤋
line eq. is y2- y1/ x2 - x1.........hence 1-6/2-3.....=-5/-1=5..................hence ans is 5
2007-05-03 10:58:20 · answer #9 · answered by pjd_0501 2 · 0⤊ 1⤋