60 students in 9th grade 25 take only chorus, 18 take only band, and 9 do not take either. How many take both?
All work please.
Thanks
2007-05-03 01:24:44 · 9 answers · asked by WMF1650 1 in Education & Reference ➔ Homework Help
Let A = students taking chorus
Let B = students taking band
A - A intersection B = 25 1)
B - A intersection B = 18 2)
(A complement) intersection (B complement) =9 3)
Total =60
A intersection B = Total - 1) -2) -3)
=60 - 25 - 18- 9
=60 - 52 = 8
Answer = 8
2007-05-03 01:41:46 · answer #1 · answered by cinu 4 · 0⤊ 1⤋
60 students - 25 only chorus - 18 only band = 17 remaining
17 students - 9 take none = 8 remaining
your answer is 8
2007-05-03 08:39:23 · answer #2 · answered by Chris 2 · 0⤊ 0⤋
60-25-18-9=8
2007-05-03 08:35:57 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Think you'd meant 60 not 90.
But yup, same idea - subtract 25, 18 and 9 and you'll get the number who do both.
PS The answer is not 4.
2007-05-03 08:35:22 · answer #4 · answered by strayinma 4 · 0⤊ 0⤋
90 total
25 take only chorus, 18 take only band, and 9 take neither, so subtract all of those from the 90.
90 - 25 - 18 - 9 = your answer
2007-05-03 08:29:11 · answer #5 · answered by FCabanski 5 · 0⤊ 1⤋
60 students- those who only take either chorus or band- those who take neither= 60- 25-18-9=8
8 students take both.
2007-05-03 08:33:26 · answer #6 · answered by cyanideprincess0008 3 · 0⤊ 1⤋
60 students
25=chorus
18=band
9 take neither
60-52=8 8 take chorus and band
2007-05-03 09:42:26 · answer #7 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
60-25-18-9=8
Hope that helps.
2007-05-03 13:34:42 · answer #8 · answered by Anonymous · 0⤊ 0⤋
Just use the formula
P(A union B) = P(A) + P(B) - P(A intersection B)
and P(only A) = P(A) - P(both)
and just proceed will arrive at the ans :)
2007-05-03 08:34:22 · answer #9 · answered by S6 2 · 0⤊ 1⤋