find f(t), where t = positive integers i.e. 1,2,3,4,....ad infinitum
where:
f(1)=3
f(2)=3*7
f(3)=3*7*11
f(4)=3*7*11*15
..... ab nauseum, ad infinitum
2007-05-02 21:40:13 · 3 answers · asked by Rey I 2 in Science & Mathematics ➔ Mathematics
Oh, one more thing, i'm just wondering if this has a non-recursive general formula.. like for a simple factorial x! it works for any value of x, without being recursive.. I need it for my power series solution for linear differential equation... thanks
2007-05-02 22:17:59 · update #1
The easiest way to do this would be to use Pi notation:
f(x) = [k=1, x]∏(4k-1)
2007-05-03 01:00:35 · answer #1 · answered by Pascal 7 · 1⤊ 0⤋
f(t) = f(t-1)*(3t+(t-1))
therefore,
f(t) = (4t-1)*f(t-1)
2007-05-03 05:42:54 · answer #2 · answered by tsunamijon 4 · 0⤊ 1⤋
f (x) = f (x-1) . (4x-1)
2007-05-03 05:11:01 · answer #3 · answered by nelaq 4 · 0⤊ 1⤋